F(x)=5x^2+10x+5

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Solution for F(x)=5x^2+10x+5 equation: 



(F)=5F^2+10F+5

We move all terms to the left:

(F)-(5F^2+10F+5)=0

We get rid of parentheses

-5F^2+F-10F-5=0

We add all the numbers together, and all the variables

-5F^2-9F-5=0

a = -5; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·(-5)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation

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